SQL : weekofyear

一天在一年中的第几个星期?

mysql> select current_date();
+----------------+
| current_date() |
+----------------+
| 2020-04-05     |
+----------------+

mysql> select weekofyear(current_date());
+----------------------------+
| weekofyear(current_date()) |
+----------------------------+
|                         14 |
+----------------------------+
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13

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